A particle (q = –4.0 µC, m = 5.0 mg) moves in a uniform magnetic field with a velocity having a magnitude of 2.0 km/s and a direction that is 50° away from that of the magnetic field. The particle is observed to have an acceleration with a magnitude of 5.8 m/s2. What is the magnitude of the magnetic field?

The magnitude of the magnetic field is 4.73 T.

Explanation:

Given that,

Charge of the particle,

It is moving with a velocity of 2 km/s and a direction that is 50° away from that of the magnetic field. The particle is observed to have an acceleration with a magnitude of 5.8 m/s². We need to find the magnitude of magnetic field.

When it enters in magnetic field,

B is magnetic field

So, the magnitude of the magnetic field is 4.73 T.

it about 600 mph from what i calculated

the force represented by vector a is normal force. if the hockey puck is moving to the right, when it is hit with a significant force by the hockey stick the puck will move off in a different direction. correct on edge.