A bicyclist travels in a circle of radius 26.4 m at a constant speed of 7.33 m/s. The bicycle-rider mass is 82.0 kg. Calculate the magnitudes of (a) the force of friction on the bicycle from the road and (b) the net force on the bicycle from the road.

(a) 166.89 N.

(b) 820.75 N

Explanation:

(a)

From the question, The horizontal component of force that act on the bicycle = Frictional Force.

Fr = mv²/r Equation 1

Where Fr = Frictional force, m = mass of bicycle-ride, v = velocity of  the bicycle rider, r = radius of the circle.

Given: m = 82 kg, v = 7.33 m/s, r = 26.4 m

Substitute into equation 1

Fr = 82(7.33²)/26.4

Fr = 4405.7698/26.4

Fr = 166.89 N.

(b)

Net force on the bicycle = √(Fr²+Fv²)

F' = √(Fr²+Fv²) Equation 2

Where F' = Net force on the bicycle, Fv = Vertical force,

But,

Fv = mg Equation 3

Where g = acceleration due to gravity.

Given: m = 82 kg, g = 9.8 m/s²

Substitute into equation 3

Fv = 82(9.8)

Fv = 803.6 N

Substitute into equation 2

F' = √(166.89²+803.6²)

F' = √(673625.23)

F' = 820.75 N

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.