What is the value of the equilibrium constant for the reaction between al(s) and cd2+(aq) at 25°c? enter your answer in scientific notation?

The value of the equilibrium constant is 5× 10¹²⁷ .

The balanced equation for the redox reaction is shown below.

2Al(s) + 3Cd²⁺(aq)> 2Al³⁺(aq) + 3Cd(s)

The number of electrons transferred in the reaction is 6

E°cell= -0.40-(-1.66)=1.26V

E°cell = 0.0592/n log K

1.26= 0.0592/6 log K

log K= 1.26/9.87×10⁻³

log K= 127.7

K= Antilog 127.7

K= 5×10¹²⁷

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5×10^127

Explanation:

Balanced redox reaction equation

2Al(s) + 3Cd^2+(aq)> 2Al^3+(aq) + 3Cd(s)

Number of electrons transferred= 6

E°cell= -0.40-(-1.66)=1.26V

From

E°cell = 0.0592/n log K

1.26= 0.0592/6 log K

log K= 1.26/9.87×10^-3

log K= 127.7

K= Antilog 127.7

K= 5×10^127

and 1and 1

your answer is c! hope this : )