An electron that has a velocity with x component 1.6 × 106 m/s and y component 2.4 × 106 m/s moves through a uniform magnetic field with x component 0.025 T and y component -0.16 T.

(a) Find the magnitude of the magnetic force on the electron.
(b) Repeat your calculation for a proton having the same velocity.

(a) 5.056 x 10^-14 N

(b) 5.056 x 10^-14 N

Explanation:

X component of velocity of electron is 1.6 × 10^6 m/s

Y component of velocity of electron is 2.4 × 10^6 m/s

X component of magnetic field is 0.025 T

Y component of magnetic field is  -0.16 T

charge on electron, q = - 1.6 x 10^-19 C

Write the velocity and magnetic field in the vector forms.

The force on the charge particle when it is moving in the magnetic field is given by

(a) Force on electron is given by

Magnitude of force is 5.056 x 10^-14 N.

(b) Force on a proton is given by

Magnitude of force is 5.056 x 10^-14 N.

Thus, the magnitude of force remains same but the direction of force is opposite to each other.

Explanation:

answer: question1

1,000 tons

question2

3: 8

question 3

store d

step-by-step explanation:

the answer is to check all of them! they all apply well at least i think so!