Physics, 16.04.2020 01:12 Airport12lt

Eventually, the process approaches a steady state. In that steady state, the charge of the capacitor is not changing. What is the current in the circuit in the steady state? View Available Hint(s) Eventually, the process approaches a steady state. In that steady state, the charge of the capacitor is not changing. What is the current in the circuit in the steady state? ER ER+C ER−C EC−R zero

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Answer from: carterhoward

The current in the circuit when the charge of the capacitor is not changing is 0 A.

Explanation:

This question is describing a RC circuit connected to a battery with Emf of E.

The battery charges the capacitor from when the voltage across the capacitor is zero to when it is fully charged at steady state when the charge on the capacitor stops changing.

The current in the circuit at any time can be evaluated in two ways.

The current in the circuit at anytime is the current the flows through the capacitor at that particular time period.

And the current flowing through a capacitor is given as the time derivative of the charge of the capacitor.

I = (dq/dt)

At steady state, when q is not changing with time, (dq/dt) = 0

Hence, the current in the circuit too, at this point is 0 A.

- The second method

The current in the circuit at anytime cam be obtained by dividing the voltage difference between the battery and the capacitor at any time with the Resistance of the resistor.

I = (E - V꜀)/R

Note V꜀ = voltage across the capacitor at any time.

When the charge of the capacitor is not changing, it means the capacitor is fully charged and the voltage across the capacitor has now matched the emf of the battery charging it.

when V꜀ = E

I = (E - V꜀)/R = (E - E)/R = 0 A

Hope this Helps!!!

Answer from: Quest

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

$p(t)=0.3t^2+6t+80$

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

$p(0)=0+0+80=80$

according to question, we have said that if the population has twice its initial population, then it becomes

$p(t)=2\times 80=160$

so, time taken to reach this above mentioned population is given by

$160=0.3t^2+6t+80\\\\160-80=0.3t^2+6t\\\\80=0.3t^2+6t\\\\0.3t^2+6t-80=0\\\\\text{using quadratic formula ,we get }\\\\t_{1,\: 2}=\frac{-60\pm \sqrt{60^2-4\cdot \: 3\cdot \: 800}}{2\cdot \: 3}\\\\t=-29.14\ and\ t=9.149$

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

Answer from: Quest

it is b. absorbs thermal energy

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