An ice skater is spinning at 6.2 rev/s and has a moment of inertia of 0.36 kg ⋅ m2. show answer No Attempt 33% Part (a) Calculate the angular momentum, in kilogram meters squared per second, of the ice skater spinning at 6.2 rev/s. L1 = | sin() cos() tan() cotan() asin() acos() atan() acotan() sinh() cosh() tanh() cotanh() Degrees Radians π ( ) 7 8 9 HOME E ↑^ ^↓ 4 5 6 ← / * 1 2 3 → + - 0 . END √() BACKSPACE DEL CLEAR Grade Summary Deductions 0% Potential 100% Submissions Attempts remaining: 3 (4% per attempt) detailed view Hints: 4% deduction per hint. Hints remaining: 1 Feedback: 5% deduction per feedback. No Attempt No Attempt 33% Part (b) He reduces his rate of rotation by extending his arms and increasing his moment of inertia. Find the value of his moment of inertia (in kilogram meters squared) if his rate of rotation decreases to 1.25 rev/s. No Attempt No Attempt 33% Part (c) Suppose instead he keeps his arms in and al