Physics, 20.04.2020 19:09 jahnoibenjamin

Read the intro to lab 10. We are going to assume that the experiment was done in a styrofoam cup, so we are not going to include the heat gained by the cup or the stirrer, A piece of hot metal is put into cool water. Conservation of energy requires that heat lost = heat gained. So, m c delta T for water = m c delta T for the metal. c for water is 4,19 j/gC Data: mass of water = 100 g starting temp of water = 20 C mass of metal = 60 g starting temp of metal = 100 C Final temp of water and metal = 24 C Calculate the specific heat of the metal, determine what metal it might be from the list in the lab manual and calculate a percent error. Enter the result of your calculations in the quiz named specific heat. It will count as a lab.

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Read the intro to lab 10. We are going to assume that the experiment was done in a styrofoam cup, so...

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