Consider 500 g of silver (atomic mass 107 g/mol). Assume that the temperature is high enough that equipartition applies. We heat the silver by immersing it in water; by measuring the temperature change of the water we compute that 300 J of heat energy entered the silver.

What was the change in temperature of the silver?

A. 2.57 K
B. 0.6 K
C. 4.99 K
D. 169 K
E. 0.0466 K

A. 2.57 K

Explanation:

From specific heat capacity,

Q = cmΔT Equation 1

Where Q = Amount of heat that entered into silver, m = mass of silver, c = specific heat capacity of silver, ΔT = change in temperature of the silver.

make ΔT the subject of the equation

ΔT = Q/cm Equation 2

Given: Q = 300 J, m = 500 g = 0.5 kg

Constant: c = 233 J/kg.K

Substitute into equation 2

ΔT = 300/(0.5×233)

ΔT  = 300/116.5

ΔT = 2.57 K

Hence the right option is A. 2.57 K

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