Magnetic Levitation (maglev) trains use electricity to generate magnetic fields. How are these magnetic fields related to the forward motion of the train? A) Electricity is used to generate a magnetic field opposite that of the train so the train is pulled forward along a frictionless surface. B) Electricity is used to generate a magnetic field of the same polarity as that at the base of the train. This elevates the train and also moves it forward. C) Electricity generates a magnetic field as it flows through coils on the train. A large electromagnetic at the opposite end of the track pulls the train to its destination and lifts it off the track. D) A current below the train generates a magnetic field that levitates the train, by using the repulsion of like charges. Electricity flows through coils on the side of the track, as the current alternates it pulls the train forward and pushes it from the back.

An charge with mass m and charge q is emitted from the origin, (x,y)=(0,0). a large, flat screen is located at x=l. there is a target on the screen at y position y(h), where y(h) > 0. in this problem, you will examine two different ways that the charge might hit the target. ignore gravity in this problem. 1.assume that the charge is emitted with velocity v(0) in the positive x direction. between the origin and the screen, the charge travels through a constant electric field pointing in the positive y direction. what should the magnitude e of the electric field be if the charge is to hit the target on the screen? express your answer in terms of m, q, y(h), v(0), and l. 2.now assume that the charge is emitted with velocity v(0) in the positive y direction. between the origin and the screen, the charge travels through a constant electric field pointing in the positive x direction. what should the magnitude e of the electric field be if the charge is to hit the target on the screen? express your answer in terms of m, q, y(h), v(0), and l.