During a football game, a receiver has just caught a pass and is standing still. Before he can move, a tackler, running at a velocity of 3.40 m/s, grabs and holds onto him so that they move off together with a velocity of 1.70 m/s. If the mass of the tackler is 133 kg, determine the mass of the receiver. Assume momentum is conserved.

133 kg

Explanation:

Parameters given:

Mass of tackler, m = 133 kg

Initial velocity of tackler, u = 3.4 m/s

Final velocity of tackler and receiver, v = 1.7 m/s

Since momentum is conserved, we apply the principle of conservation of momentum:

Total initial momentum = Total final momentum

mu + MU = (m + M)v

Where U = initial velocity of receiver = 0 m/s

M = mass of receiver

Therefore:

(133 * 3.4) + (M * 0) = (133 + M) * 1.7

452.2 = (133 + M) * 1.7

(133 + M) = 452.2/1.7

133 + M = 266

=> M = 266 - 133

M = 133 kg

The mass of the receiver is 133 kg.

well, you would divide 135 by 33 to get your answer. then that is how many seconds it would take. boardman should fly about 132 m or 4.090909090909091 seconds.

d) physical means can be used to separate the components of air.