A guitar string vibrates at a frequency of 330Hz with wavelength 1.40m. The frequency and wavelength of this sound wave in air (20 C) when it reaches our ears is: Lower frequency, same wavelength Same frequency, same wavelength Higher frequency, same wavelength Same frequency, shorter wavelength

Same frequency, shorter wavelength

Explanation:

The speed of a wave is given by

where,

f = Frequency

= Wavelength

It can be seen that the wavelength is directly proportional to the velocity.

Here the frequency of the sound does not change.

But the velocity of the sound in air is slower.

Hence, the frequency remains same and the wavelength shortens.

the answer is kevlar

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft