To practice Problem-Solving Strategy 27.1: Magnetic Forces. A particle with mass 1.81×10−3 kgkg and a charge of 1.22×10−8 CC has, at a given instant, a velocity v⃗ =(3.00×104m/s)j^v→=(3.00×104m/s)j^. What are the magnitude and direction of the particle’s acceleration produced by a uniform magnetic field B⃗ =(1.63T)i^+(0.980T)j^B→=(1.63T)i^+( 0.980T)j^?

The magnitude of the acceleration  is

The direction is i.e the negative direction of the z-axis

Explanation:

 From  the question we are that

       The mass of the particle

         The charge on the particle is

         The velocity is

        The the magnetic field is  

The charge experienced  a force which is mathematically represented as

    Substituting value

Note :

Now force is also mathematically represented as

Making a the subject

   Substituting values

change tension