Two rather unequal cars are competing in a drag race. For simplicity, let's assume that the accelerations of the cars are constant. Car 1 has an acceleration of 3.3 m/s2, while Car 2 has an acceleration of 5.9 m/s2. Car 2 gets off to a late start, 0.5 seconds after Car 1.

1. At what time after Car 1 took off will it be overtaken by Car 2?
2. How far down the track will this happen?
3. How much faster will Car 2 be than Car 1 by that time?

car1: a=3.1m/s^2 , car2: a=6.1m/s^2

(a) 1/2*3.1*t^2= 1/2*6.1*(t-0.9)^2

1.55t^2= 3.05(t^2-1.8t+0.81)= 3.05t^2-5.49t+2.4705

1.5t^2-5.49t+2.4705= 0

t= 3.13457 = 3.14[s] after.

(b) d= 1/2*3.1*3.13457^2= 15.23[m] approx.

(c) car1: v=at = 3.1*3.13457= 9.717m/s

car2: v=at = 6.1*(3.13457-0.9)= 13.631m/s

13.631-9.717= 3.914 = 3.91[m/s] faster than car1.

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia