An greenhoopwith mass mh= 2.5 kg and radius Rh= 0.16 m hangs from a string that goes over a blue soliddiskpulley with mass md= 1.9 kg and radius Rd= 0.1 m. The other end of the string is attached to a massless axel through the center of an orange sphere on a flat horizontal surface that rolls without slipping and has mass ms= 3.5 kg and radius Rs= 0.23 m. The system is released from rest.

1)What is magnitude of the linear acceleration of the hoop?2)What is magnitude of the linear acceleration of the sphere?3)What is the magnitude of the angular acceleration of the disk pulley?4)What is the magnitude of the angular acceleration of the sphere?5)What is the tension in the string between the sphere and disk pulley?6)What is the tension in the string between the hoop and disk pulley?7)The green hoop falls a distance d = 1.54 m. (After being released from rest.)8 How much time does the hoop take to fall 1.54 m?9 What is the magnitude of the velocity of the green hoop after it has dropped 1.54 m?

The modern-day generator works on the principle of electromagnetic induction discovered by michael faraday in 1831-32. faraday discovered that the above flow of electric charges could be induced by moving an electrical conductor, such as a wire that contains electric charges, in a magnetic field.

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s