If a certain shade of blue has a frequency of 7.33 x 10^14hz what is the energy of exactly one photon of this light. is this as simple as multiplying the frequency by planck's constant?

In calculating the energy of a photon of light, we need the relationship for energy and the frequency which is expressed as:
 
E=hv

where h is the Planck's constant (6.626 x 10-34 J s)and v is the frequency.
E = 6.626 x 10-34 J s (7.33 x 10^14 /s) = 4.857 x 10^-19 J

The objects do not reach terminal velocity         there is not enough time from the time the object falls from when it hits the ground to achieve terminal velocity. an object must be placed higher to achieve terminal velocity in order to be in free fall.