A 8.48-kg box is sliding across the horizontal floor of an elevator. The coefficient of kinetic friction between the box and the floor is 0.415. Determine the kinetic frictional force that acts on the box when the elevator is (a) stationary, (b) accelerating upward with an acceleration whose magnitude is 1.91 m/s2, and (c) accelerating downward with an acceleration whose magnitude is 1.91 m/s2.

(a) 34.48N

(b) 27.7664N

(c)41.209N

Explanation:

Following relation gives force of kinetic friction.

, u is coefficient of of kinetic friction , is force normal or perpendicular to surface which is given by , a is acceleration normal to surface.

In case of b and c, a is varied because of the acceleration of elevator and in case a it remains because elevator is stationary and acceleration is only due to earth's gravity.

so in case b and in case c (it is net acceleration ).

substituting all this in original relation gives.

(a)

(b).

(c) .

get the total number of pieces of fruit and divide it by 4 to get the average. the result is the answer to the problem. 14 total number of fruits and there are 4 members. 14 divided by 4 is equals to 3.5.