A wire of length 2.80 m is sitting in a region of space where there is a uniform magnetic field. The current in the wire is 4.80 A and the magnitude of the magnetic field is 0.320 T. For the following angles between the direction of current in the wire and the direction of the magnetic field, find the magnitude of the magnetic force on the wire.

Answer

Given,

Length of the wire, L = 2.80 m

Current in the wire, I = 4.80 A

Magnetic field, B = 0.32 T

θ be the angle between force and magnetic field.

F = IBL sin θ

F = 4.80 x 0.32 x 2.80 x sin θ

F =  4.3 sin θ

Assuming θ = 60°

Now, Force

F = 4.3 x sin 60°

F = 3.725 N

Now, if θ = 90°

F = 4.3 x sin 90°

F = 4.3 N

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.