A ball with a weight of 0.5 N is submerged under water and then released. There is a net force of 5 N upwards. what is the buyoant force ,
a) 4.5 n upward
b)5 n downward
c) 2.5 n upward
d)5.5 n downward

That depends on what kind of environ meant it is in  in space it has the same force that was applied when the velocity was gained

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.