3. En una carrera cuyo recorrido es recto, una moto circula durante 30 segundos hasta alcanzar una velocidad de 162.00km/h. Si la aceleración sigue siendo la misma, ¿cuánto tiempo tardará en recorrer los 200 metros que faltan para rebasar la meta y a qué velocidad lo hará?

Explanation:

I will answer in English.

The translated question is:

1. Time

First, you must calculate the acceleration, a,  starting from rest (V₀ = 0), with a time fo 30 seconds, and final veloficty, V₁, of 162.00km/h.

Convert 162.00km/h to m/s:

Now, you can calculate the time to travel 200 meters

The most direct equation is;

Where you know:

Use the quadratic formula with a = 0.75, b = 45, and c = -200

Discard the negative value. The positive value is t = 4.1565s

Round to one significant figure: 4s ← answer

2. Velocity

The speed or magnitude of velocity may be calculated using the equation:

With:

28. evolution

29. environment, survive, offspring  

explanation:

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.