An amusement park ride consists of airplane-shaped cars attached to steel rods. Each rod has a length of 15m and a cross-sectional area 8.00cm^2. Take Young's modulus for steel to be Y= 2.0 x 10^11 Pa.
How much is the rod stretched (change in length of) when the ride is at rest? Assume that each car with two people seated in it has a total weight of 1900 N.

Explanation:

Given that,

Length of each rod, L = 15 m

Area of cross section of the rod,

Young's modulus for steel,

Total weight of two people, F = 1900 N

We need to find the stretching in the rod when the ride is at rest. The formula of Young's modulus of a material is given by :

Here, is the stretching in the rod

So, the rod will stretched to

c

explanation:

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.