A common technique in analysis of scientific data is normalization. The purpose of normalizing data is to eliminate irrelevant constants that can obscure the salient features of the data. The goal of this experiment is to test the hypothesis that the flux of light decreases as the square of the distance from the source. In this case, the absolute value of the voltage measured by the photometer is irrelevant; only the relative value conveys useful information. Suppose that in Part 2.2.2 of the experiment, students obtain a signal value of 185 mV at a distance of 4 cm and a value of 82 mV at a distance of 6.2 cm. Normalize the students' data to the value obtained at 4 cm. (Divide the signal value by 185.) Then calculate the theoretically expected (normalized) value at 6.2 cm. Normalized experimental value at 6.2 cmTheoretically expected normalized value at 6.2 cm

1. Normalized value at 6.2 cm = 0.443

2. Theoretical expected value = 0.416

Explanation:

1. Normalized experimental value is calculated as follows;

Normalized experimental value = 82/185

                                                    = 0.443

Therefore, normalized value at 6.2 cm = 0.443

2. Calculating the theoretical expected value using the relation;

V₁r₁² = V₂r₂²

V₂ = V₁(r₁/r₂)²

    = 1* (4/6.2)²

    = 1 *0.645²

     = 0.416

Therefore, the theoretical expected value = 0.416

they should be similar or the same

hello, i am papaguy.

i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!