Particle q1 has a positive 6 µC charge. Particle q2 has a positive 2 µC charge. They are located 0.1 meters apart.

Recall that k = 8.99 × 109 N•meters squared per Coulomb squared.

What is the force applied between q1 and q2?

F = 10.788 N

Explanation:

Given that,

Charge 1,

Charge 2,

Distance between charges, d = 0.1 m

We know that there is a force between charges. It is called electrostatic force. It is given by :

So, the force applied between charges is 10.788 N.

wavelength divides in half and speed stays the same.

it is a negative acceleration