The amount of electric energy consumed by a 60.0-watt lightbulb for 1.00 minute could lift a
10.0-newton object to a maximum vertical height of
A) 6.00 m B) 36.7 m C) 360. m D) 600. M

Explanation:

Given that,

Amount of energy consumed by a 60W light bulb for 1 minutes

P = 60 W

t = 1 mins = 60seconds

This energy can be used to lift a body that weight 10N

W = 10N

This shows that the electrical energy is converted to potential energy

Let calculate the electrical energy

Power is the rate of doing work

Power = Work / time

Therefore, work = power × time

Work = 60 × 60

Work = 3600 J

Potential energy can be calculated using

P.E = mgh

Where, weight is

W = mg

Then, P.E = W•h

P.E = 10•h

Then,

Potential energy, = Electrical energy

P.E = Work

10•h = 3600

Divide both sides by 10

h = 3600 / 10

h = 360m

So, the object will be lifted to a height of 360m

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y