Please HELP! WILL GIVE BRAINLIEST!
A mass of 500 g is attached to a spring with elastic constant coefficient of elasticity = 50.0 N / m. The spring is lengthened by 10 cm and then left free. Calculate the return force exerted by the spring.

Force, F = -5 N                  

Explanation:

We have,

Mass, m = 500 g = 0.5 kg

Spring constant of the spring, K = 50 N?M

The spring is lengthened by 10 cm and then left free.

It is required to find the return force exerted by the spring. It is based on Hooke's law. The force on the spring is given by :

So, the return force exerted by the spring is (-5 N)

energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this

hi,

what occurs during a solar eclipse?

there are small tides across earth.

the moon is between earth and the sun.

p.s. im not sure if the first answer is correct because during a solar ecliphse there are spring tides and i dont know if they are the same.