A 75 kg bungee jumper jumps off with zero initial speed from a high cliff with a bungee cord tied to her ankle. At some time during the jump, the bungee cord starts stretching. The lowest point in her jump where the bungee cord is at maximum stretch is a total drop of 195 m . What is the elastic potential energy stored in the bungee cord at the instant she reaches this lowest point?

The elastic potential energy PE=143.47kJ

Explanation:

This problem bothers on the potential energy stored in a material.

Given data

Mass of the bungee jumper

m= 75kg

Height of jump down the cliff h=195m

We know that the elastic potential energy stored is same as the potential energy of the bungee jumper

PE= 1/2kx²= mgh

Assuming g is 9.81m/s²

PE= 75*9.81*195

PE= 143471.25J

PE=143.47kJ

What is potential energy?

Potential energy is the energy possessed by a body by virtue of it position.

the answer is 3.1 his answer is wrong mines is right

it is a negative acceleration