The weight of a bicyclist and bicycle together is 51.0kg how much work has been done if the bicyclist slows down the bicycle from a seed of 3.95 m/s to 1.31 m/s

The work done is 354.1032 Joules

Explanation:

To answer the question we note that the amount of work done is equivalent to the reduction in the kinetic energy of the bicyclist and bicycle.

Therefore, initial kinetic energy. KE of the system is given by the following relation;

Final kinetic energy

Where:

v₁ = Initial velocity = 3.95 m/s

v₂ = Final velocity = 1.31 m/s

m = Mass of the bicyclist and bicycle = 51.0 kg

Change in kinetic energy ΔKE;

Therefore, work done = -ΔKE = 354.1032 Joules.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

real, smaller and upside-down.   so the answer should be b.