Suppose an automobile has a kinetic energy
of 2300 J.
When it moves with six times the speed,
what will be its kinetic energy?
Answer in units of J.

Explanation:

Given that,

Kinetic energy of an automobile is 2300J

K.E = 2300J

The formula for kinetic energy is

K.E = ½mv²

So, if the speed of the automobile is increased by 6, what is the kinetic energy

Now v' = 6v.

The mass of the automobile is constant.

Therefore, the kinetic energy is

K.E' = ½mv'²

Where v' = 6v

K.E' = ½m(6v)²

K.E' = ½m × 36v²

K.E' = 36 × ½mv²

Where, from above ½mv² = 2300J

Then,

K.E' = 36 × 2300 = 82,800J

The kinetic energy of the automobile when it increase it's speed is 82,800J

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.