Physics, 06.05.2020 03:43 jadahilbun01

G Two cars, car 1 and car 2 are traveling in opposite directions, car 1 with a magnitude of velocity v1=13.0 m/s and car 2 v2= 7.22 m/s. If car 1’s exhaust system is loud enough to be heard by car 2 and the frequency fe produced from the exhaust is 2.10 kHz. What frequencies would be heard by car 2 when the cars are approaching, passing, and retreating from one another?

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Answer from: Bra1nPowers

When they are approaching each other

$f_a = 2228.7 \ Hz$

When they are passing each other

f_a = 2100Hz

When they are retreating from each other

f_a = 1980.7 Hz

Explanation:

From the question we are told that

The velocity of car one is v_1 = 13.0 m/s

The velocity of car two is v_2 = 7.22 m/s

The frequency of sound from car one is f_e = 2.10 kHz

Generally the speed of sound at normal temperature is v = 343 m/s

Now as the cars move relative to each other doppler effect is created and this can be represented mathematically as

$f_a = f_o [\frac{v \pm v_o}{v \pm v_s} ]$

Where v_s is the velocity of the source of sound

v_o is the velocity of the observer of the sound

f_o is the actual frequence

f_a is the apparent frequency

Considering the case when they are approaching each other

$f_a = f_o [\frac{v + v_o}{v - v_s} ]$

v_o = v_2

v_s = v_1

f_o = f_e

Substituting value

$f_a = 2100 [\frac{343 + 7.22}{ 343 - 13} ]$

$f_a = 2228.7 \ Hz$

Considering the case when they are passing each other

At that instant

v_o = v_s = 0m/s

f_o = f_e

$f_a = f_o [\frac{v }{v } ]$

f_a = f_o

Substituting value

f_a = 2100Hz

Considering the case when they are retreating from each other

$f_a = f_o [\frac{v - v_o}{v + v_s} ]$

v_o = v_2

v_s = v_1

f_o = f_e

Substituting value

$f_a = 2100 [\frac{343 - 7.22}{343 + 13} ]$

f_a = 1980.7 Hz

Answer from: Quest

Ifound this on google “your outer ear collects sound waves and reflects them into a tiny tube called the ear canal. at the end of the ear canal is a thin, skin-like membrane stretched tightly over the opening, called the eardrum.” i hope this you for what your looking for

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r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .

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