When a charge is accelerated through a potential difference of 500 V, its kinetic energy increases from 2.0 x 10^ -5 J to 6. 0 x 10^ -5 J. What is the magnitude of the charge?
2 points
a. 4.0 x 10 -8 C
b. 8.0 x 10 -8 C
c. 1. 2 x 10 -7 C
d. 1. 6 x 10 -7 C

good looking response

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

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need to see circuit to get time constant