A flashlight beam is directed at a swimming pool in the dark at an angle of 46° with respect to the normal to the surface of the water. What is the angle of refraction of the beam in the water? ( The refractive index for water is 1.33.)

the angle of refraction of the beam is 33 degrees

Explanation:

Given that the

Incident angle I = 46°

Refractive index n = 1.33

According to Snell law,

Refractive index = ratio of sine of incidence to the sine of reflection.

That is

n = sin i/sin r

Substitute n and I Into the formula above.

1.33 = sin 46/sin r

Make sin r the subject of the formula

Sin r = sin 46/1.33

Sin r = 0.540

Find the sine inverse of r

r = sin^-1(0.540)

r = 32.7 degree

r = 33 degree approximately

the rearrangement of particles in a physical change. hope this

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.