The a992 steel rod bc has a diameter of 50 mm and is used as a strut to support the beam. determine the maximum intensity w of the uniform distributed load that can be applied to the beam without risk of causing the strut to buckle. take f. s. = 2 against bucklin

w = 11.211 KN/m

Explanation:

Given:

diameter, d = 50 mm

F.S = 2

L = 3

Due to symmetry, we have:

To find the maximum intensity, w, let's take the Pcr formula, we have:

Let's take k = 1

Substituting figures, we have:

Solving for w, we have:

w = 11211.14 N/m = 11.211 KN/m

Since Area, A= pi * (0.05)²

. This means it is safe

The maximum intensity w = 11.211KN/m

i wanna say it’s between b and d, leaning more towards b.

i think the answer would be b