A beam of electrons is incident on a single slit that has a width of 1.00 × 10–6 m and a diffraction pattern is observed on a screen located 15.0 m from the slit. The momentum of an individual electron in the beam is 5.91 × 10–24 kg ⋅ m/s. What is the width of the central maximum fringe?

w = 5.04 mm

Explanation:

To find the width of the central maximum you use the following formula for the height of the dark fringes:

   ( 1 )

y: height of the m-th dark fringe

λ: wavelength of the electron

D: distance to the screen = 15.0m

d: distance between slits = 1.00*10^{-6} m

twice the height of the first dark fringe (m = 1) gives you the width of the central peak.

You first calculate the wavelength of the electron by using the Broglie's relation:

where you have used the constant's Planck h.

Next, you replace the values of the parameters in the equation ( 1 ) with m=1:

the width of the central maximum is:

nec chapter 5 contains

c. information on special occupancy areas

nec chapter 6 covers

a. special equipment

which of the following rules contain the words shall or shall not and must be adhered to?

b. mandatory rules

which of the following rules identify actions that are allowed but not required and typically cover options or alternative methods?

c. optional rules

which of the following serves as the introduction to the nec and provides an overview of the book?

a. nec article 90

organizations that test products for safety are

c. nrtls

the nec is published by the

a national fire protection association

the nec is divided into

b. 9 chapters

the nec provides informative annexes for

c. informational materials and examples

two terms from nec article 100 that trainees should become familiar with are

b. labeled and listed

explanation:

not too sure thinking all accelerations are pointed down