A 2.2 m -long wire carries a current of 7.2 A and is immersed within a uniform magnetic field B⃗ . When this wire lies along the +x axis, a magnetic force F⃗ =(−2.6j)N acts on the wire, and when it lies on the +y axis, the force is F⃗ =(2.6i−4.4k)N.

Explanation:

Given that :

The current I =  7.2 A

The length vector L =   2.2 m i  

The force vector is = -2.6 j N

When L = 2.2 m i ; the

Force vector F = (2.6 i - 4.4 k) N

Compute the components of the magnetic field as follows:

Replacing 7.2 A for I ; -2.6 j N for F & 2.2 m i for L

However in y direction ; we have :

Hence, the component of magnetic field is as follows:

another example of kinetic energy would be,

kinetic energy   >     moving energy

answer   >   letter choice (c),   a hammer falling off a table.

hope that !                                         : )