A 53.4 kg ice skater is at rest when she throws a 0.135 kg snowball east at 15.8 m/s. What is her velocity afterwards?

thank you in advance for your help!

Her velocity afterwards is 0.04 m/s to the west.

Explanation:

Using the conservation of momentum, we have that:

m1u1 + m2u2 = m1v1 + m2v2

Where m is the mass, u is the inicial velocity and v is the final velocity.

The inicial momentum is zero, because the ice skater and the snowball are at rest (u1 = 0 and u2 = 0)

The mass of the snowball is m1 = 0.135 kg and the final velocity is v1 = 15.8 m/s, so the momentum of the snowball is:

m1 * v1 = 0.135 * 15.8 = 2.133 kg*m/s

So from the conservation of momentum, we have that:

0 = 2.133 + m2v2

m2v2 = -2.133

The mass of the ice skater is m2 = 53.4 kg, then we have that:

53.4 * v2 = -2.133

v2 = -2.133 / 53.4 = -0.0399 m/s

Her velocity afterwards is 0.04 m/s to the west.

answer: question1

1,000 tons

question2

3: 8

question 3

store d

step-by-step explanation:

you go to your settings preference and in the end youll see sth that says "i want to delete my acc" click on it and u'll acc will be deleted but u have to wait.