Two speakers create identical 240 Hz sound waves. A person is 1.47 m from Speaker 1. What is the MINIMUM distance to Speaker 2 for there to be destructive interference at that spot? (Hint: v= lambda f=343 m/s) (Unit = m)

2.90 metres

Explanation:

Distance of speaker 2 =?

Distance of speaker 1 = 1.47m

Velocity = 343

f = 240Hz

For constructive interference to occur:

Difference in distance or path = wavelength

For minimum distance, n = 1

Distance 2 - distance 1 = nλ

Recall λ = v/f

V = Velocity ; f = frequency

Distance 2 - distance 1 = v/f

Distance 2 - 1.47 = (343/240)

Distance 2 = 1.429 + 1.47

Distance 2 = 2.899 meters

Minimum Distance of speaker 2 for their to be constructive interference = 2.90meters

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft