A positive test charge of 5.0 x 10^-4 C is in an electric field that exerts a force of 2.5 x 10^-4 N on it. What is the magnitude of the electric field at the location of the test charge?

E = 0.5N/C

Explanation:

In order to calculate the magnitude of the electric field you use the following formula:

q: charge = 5.0*10^-4 C

F: force on the charge = 2.5*10^-4N

You replace the values of q and F in the equation for E:

hence, the magnitude of the electric field at the position of the carge is 0.5N/C

what experimental evidence led scientists to change from the previous model to this one?

a few of the positive particles aimed at a gold foil seemed to bounce back.

the colors of light emitted from heated atoms had very specific energies.

experiments with water vapor showed that elements combine in specific proportions.

cathode rays were bent in the same way whenever a magnet was brought near them.

the journeys of marquette, joliet and la salle a) new france expand.

all three of these explorers explored the midwest and the area around the great lakes, which they subsequently claimed for france.

this was a big portion of territory and expanded new france which before then only consisted of quebec province in northeastern canada