Answer ASAP!! Two cars equal mass (1,000 kg each) involved in a rear wnd accident at a stop sign. Here is what you know.

. Car 1 approached intersection from the top at 25 meter hill.

. Car 2 was on a flat stretch of road directly in front of Car 1

. At the bottom of the hill, Car 1 was going 20 m/s, Car 2 at 30 m/s before it stopped at the stop sign.

. There was no skid marks left by Car 2. The collision occurred at the stop sign, where car 2 had stopped.

. After the collision, both cars were moving together in the same direction at 10 m/s before slowly rolling to a stop.

. You must now push Car 2, using 800N of force, 10 meters off to the side of the road so no one gets hurt.

4) How much work was done to bring Car 2 to a stop?

5) If a Car 2 came to a stop in 15 seconds, how much power (in watts) did it take to stop Car 2 at the stop sign by applying force to the brakes?

6) What is the final combined momentum of the cars right after the accident?

When the force acting on an object points at least partially in the direction of the motion the work done is considered to be negative

Why are graphs useful when interpreting data

Amass m = 74 kg slides on a frictionless track that has a drop, followed by a loop-the-loop with radius r = 18.4 m and finally a flat straight section at the same height as the center of the loop (18.4 m off the ground). since the mass would not make it around the loop if released from the height of the top of the loop (do you know why? ) it must be released above the top of the loop-the-loop height. (assume the mass never leaves the smooth track at any point on its path.) 1. what is the minimum speed the block must have at the top of the loop to make it around the loop-the-loop without leaving the track? 2. what height above the ground must the mass begin to make it around the loop-the-loop? 3. if the mass has just enough speed to make it around the loop without leaving the track, what will its speed be at the bottom of the loop? 4. if the mass has just enough speed to make it around the loop without leaving the track, what is its speed at the final flat level (18.4 m off the ground)? 5. now a spring with spring constant k = 15600 n/m is used on the final flat surface to stop the mass. how far does the spring compress?