The boy a rotating merry-go-round, his mass is 40 kg, he stands at a distance 0.90 m from the axis of a rotation. The merry-go-round can be approximated as a uniform solid disk with a mass of 450 kg and a radius of 2.10 m. Calculate the moment of inertia of this system.

Ihope you get it right bro

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Wow good luck with that answer