You push a block to the top of an inclined plane. The mechanical advantage of the plane is 5. The inclined plane is 10 meters long. What is the height of the inclined plane? 10 m
50 m
2 m
0.5 m

the answer is 2m

Explanation:

the formula to find the mechanical advantage of an inclined plane is

MA (mechanical advantage) = L (length of plane) / H (height)

for this problem we already know the MA and length. simply plug that into the formula and isolate H.... you'll end up finding the height >> 2m

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.

be subject to a force andchange its motion