PLEASE HELP 50 pts + brainliest. 3. A laser light travels from air (n=1) through water (n=1.33), and then a piece of glass (n=1.55). The light first enters the water at an angle of 25.0 degrees (from air to water). Draw a diagram. Use Snell’s Law to find the angle of refraction in the water and then in the glass. I don't know how to do this.

the angle of refraction in the water is 34.2 degrees and then in the glass is 41 degrees approximately

Explanation:

A laser light travels from air (n=1) through water (n=1.33), and then a piece of glass (n=1.55).

If the light first enters the water at an angle of 25.0 degrees (from air to water). That means

The incident angle  = 25 degrees

Using Snell' law

n(air)/n(water) = sin 25/sin R

Where R is the angle of refraction

1/1.33 = sin 25/sin R

Make sin R the subject of formula

Sin R = sin 25 / 0.7518

Sin R = 0.5620

R = sin^-1(0.5620)

R = 34.2 degrees

This angle will be an incident angle when the light is travelling from the water to glass. Using Snell law agains,

1.33/1.55 = sin 34.2/sin R

Cross multiply

1.33 sin R = 0.87122

Make R the subject of formula

Sin R = 0.87122/1.33

Sin R = 0.6550

R = sin^-1(0.6550)

R = 40.9 degrees

Therefore, the angle of refraction in the water is 34.2 degrees and then in the glass is 41 degrees approximately.

Find the attached file for the figure

the duration of a photographic flash is related to an rc time constant, which is 0.100 μs for a certain camera.