Physics, 18.06.2020 22:57 cameronbeaugh

A 60-kg skier is stationary at the top of a hill. She then pushes off and heads down the hill with an initial speed of 4.0 m/s. Air resistance and the friction between the skis and the snow are both negligible. How fast will she be moving after she is at the bottom of the hill, which is 10 m in elevation lower than the hilltop

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Answer from: jessikamacadlo8948

The velocity is v = 8.85 m/s

Explanation:

From the question we are told that

The mass of the skier is $m_s = 60 \ kg$

The initial speed is $u = 4.0 \ m/s$

The height is $h = 10 \ m$

According to the law of energy conservation

PE_t + KE_t = KE_b + PE_b

Where PE_t is the potential energy at the top which is mathematically evaluated as

PE_t = mg h

substituting values

PE_t = 60 * 4*9.8

$PE_t = 2352 \ J$

And KE_t is the kinetic energy at the top which equal to zero due to the fact that velocity is zero at the top of the hill

And KE_b is the kinetic energy at the bottom of the hill which is mathematically represented as

KE_b = 0.5 * m * v^2

substituting values

KE_b = 0.5 * 60 * v^2

=> KE_b = 30 v^2

Where v is the velocity at the bottom

And PE_b is the potential energy at the bottom which equal to zero due to the fact that height is zero at the bottom of the hill

30 v^2 = 2352

=> $v^2 = \frac{2352}{30}$

=> $v = \sqrt{ \frac{2352}{30}}$

v = 8.85 m/s

Answer from: duhfiywge8885

The Skier's velocity at the bottom of the hill will be 18m/s

Explanation:

This is simply the case of energy conversion between potential and kinetic energy. Her potential energy at the top of the hill gets converted to the kinetic energy she experiences at the bottom.

That is

$mgh = 0.5 mv^{2}$

solving for velocity, we will have

$v= \sqrt{2gh}$

hence her velocity will be

$v=\sqrt{2 \times 9.81 \times 10}=14.00m/s$

This is the velocity she gains from the slope.

Recall that she already has an initial velocity of 4m/s. It is important to note that since velocities are vector quantities, they can easily be added algebraically. Hence, her velocity at the bottom of the hill is 4 + 14 = 18m/s

The Skier's velocity at the bottom of the hill will be 18m/s

Answer from: Quest

graphing motion: mastery test

209be

what is the instantaneous acceleration of

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velocity imetersisecond

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time (seconds)

answer: 0 meters/second^2

Answer from: Quest

f=ma newton's second law 7x8=56n

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