A circular loop with radius R= 20 cm carrying a current, I= 5 A is placed in a uniform magnetic field B = 0.2 T. (a) Find the magnitude of the magnetic dipole moment of the current loop. (b) Find the maximum torque acting on the loop. (c) How much work is needed to rotate this loop in this field by 90°, starting from the initial position, 0, =0° to a final position, 0r=90° ? Hint: 0 is the angle between the magnetic dipole moment and the magnetic field

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can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

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