Se deja caer una piedra A en reposo desde un acantilado muy alto. Cuando ha caído 5 m, se deja caer una piedra B. A. Explicar ¿cómo cambia la distancia entre ambas piedras a medida que caen? B. Determina la velocidad de la piedra B cuando ha recorrido 5 m. C. En una sola gráfica velocidad vs tiempo, bosque las gráficas de las dos piedras cuando la piedra B ha recorrido 10 m. NO necesita colocar valores en las gráficas.

Here's what I get  

Explanation:

A. Distance between A and B.

h = -½gt²

The stones go faster the farther they fall.

Stone A has already reached 5 m when B is released.

When B reaches 5 m, A has dropped further and is falling even faster.

The distance between the stones increases with time.

Figure 1 shows this effect in a graph of height vs. time.

B. Speed of Stone B

v² = 2gh =2 × ( -9.81 m·s⁻²) × (-5 m) = 98.1 m·s⁻²  

v = 9.9 m/s

The stone is travelling at 9.9 m/s when it reaches 5 m.

C. Velocity vs time

v = -gt

Both stones accelerate at the same rate.

When Stone B has reached 10 m at time t, Stone A is falling much faster.

Fig. 2 shows this in a graph of velocity vs time.

the skeletons of most mammals reach a certain size and then stop growing. however, many animals, including some mammals, keep growing throughout their lives. kangaroos, for example, just keep growing and growing until they die. also, the longer an animal lives the greater the chance it might catch some deadly disease.