If an electric wire is allowed to produce a magnetic field no larger than that of the earth (0.55 x 10-4 t) at a distance of 25 cm, what is the maximum current the wire can carry?

68.75 A

Explanation:

B = 0.55 x 10^-4 T, r = 25 cm = 0.25 m

Let the current be i.

The magnetic field due to a current carrying straight wire at a distance r is given by

B = μ0 / 4π x 2 i / r

0.55 x 10^-4 = 10^-7 x 2 x i / 0.25

i = 68.75 A

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explanation: