the force of attraction between two masses is 3.60 Newtons if one of the masses is tripled and the distance between the masses is quadrupled what is the new force of attraction

F = 19.2 N

Explanation: Given that the initial Force = 3.6N

The formula involved is

F = GMm/r^2

Substitute the force F

3.6 = GMm/r^2

If one of the masses is tripled and the distance between the masses is quadrupled. We have

3.6 = (G × 3Mm)/(4r)^2

Where G will be constant.

3.6 = 3GMm/16r^2

Separate the fraction of number

3.6 = 3/16 × GMm/r^2

Make GMm/r^2 the subject of formula

(3.6 × 16)/3 = GMm/r^2

19.2 = GMm/r^2

Therefore, the new force of attraction is 19.2 N

c. 7/3

step-by-step explanation:

a rational number is like pi- it is a repeating decimal.

a. is -1.8

b. 2.236068

c. 2.3333333333333333333

d.   is 3

i hope that ! =)

50 inches should be the resultant vector