To study the properties of various particles, you can accelerate the particles with electric fields. A positron is a particle with the same mass as an electron but the opposite charge ( e). If a positron is accelerated by a constant electric field of magnitude 286 N/C, find the following. (a) Find the acceleration of the positron. m/s2
(b) Find the positron's speed after 8.70 × 10-9 s. Assume that the positron started from rest. m/s

a) a = 5.03x10¹³ m/s²

b)

Explanation:    

a) The acceleration of the positron can be found as follows:

   (1)

Also,

   (2)

By entering equation (1) into (2), we have:

Where:

F: is the electric force

m: is the particle's mass = 9.1x10⁻³¹ kg

q: is the charge of the positron = 1.6x10⁻¹⁹ C    

E: is the electric field = 286 N/C

b) The positron's speed can be calculated using the following equation:

Where:

: is the final speed =?

: is the initial speed =0

t: is the time = 8.70x10⁻⁹ s

I hope it helps you!

answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample,

so, density of rock sample will be

since, the density of rock sample is . hence, the rock sample is a sedimentary rock, whose densities varies between .