How much work is done (by a battery, generator, or some other source of potential difference) in moving Avogadro's number of electrons from an initial point where the electric potential is 9.20 V to a point where the electric potential is -6.90 V

-1486 KJ

Explanation:

The work done by an electric field on a charged body is:

W = ΔV * q

where ΔV = change in voltage

q = total charge

The total charge of Avogadro's number of electrons is:

6.0221409 * 10^(23) * -1.6023 * 10^(-19) = -9.65 * 10^(4)

The change in voltage, ΔV, is:

9.20 - (6.90) = 15.4

Therefore, the work done is:

W = -9.65 * 10^(4) * 15.4 = -1.486 * 10^6 J = -1486 KJ

The negative sign means that the motion of the electrons is opposite the electrostatic force.

answer is c

explanation:

prolly a beacuse the momentuem the car has increases while going down hill