The light intensity incident on a metallic surface with a work function of 3 eV produces photoelectrons with a maximum kinetic energy of 2 eV. The frequency of the light is doubled. Determine the maximum kinetic energy (in eV).

7ev

Explanation:

The Energy of an incident light is given as E = hf;

Where h is Planks constant

f is frequency

Also.

E = Eo + K.E

Where Eo is work function and K.E is kinetic energy.

Hence substituting the given values,

E = 3ev + 2ev = 5ev

The frequency of the incident wave if it's doubled the Energy would be doubled since E is proportional to f with other elements been constant.

Hence :E = 10ev

But K.E = E -Eo

= 10ev - 3ev = 7ev

Maximum Kinetic Energy is 7ev.

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2