A lemming running 3.22 m/s runs off a horizontal cliff. It lands in the water 7.54 m from the base of the cliff. How much time was it in the air? (Unit = s)

2.34s

Explanation:

Given the following :

Horizontal Velocity(V) = 3.22m/s

Horizontal Distance = 7.54m

Therefore, the time spent in the air can be calculated thus:

Using the relation:

Speed = distance / time

3.22m/s = 7.54m / time

Time = 7.54m / 3.22m/s

Time = 2.34s

i think it would be 5

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft