Nitrogen at an initial state of 300 K, 150 kPa, and 0.45 m3 is compressed slowly in an isothermal process to a final pressure of 800 kPa. Determine the work done during this process

W = -113.0 kJ.

Explanation:

The work done during the isothermal process is the following:        

Where:

= 150 kPa

= 0.45 m³

= 800 kPa

Therefore, the work done during this process is -113.0 kJ.

I hope it helps you!

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

it was given as a lesson and guide for prayer.